leftso 1674 0 2019-07-08 16:53:38

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本文主要讲解通过使用 Stream.concat() 方法 去合并两个stream,新的stream由原来的两个stream所有元素组成(相同元素会覆盖)。

1.Stream concat()方法基本介绍

static <T> Stream<T> concat(Stream<? extends T> firstStream,
                            Stream<? extends T> secondStream)
  • 此方法创建一个延迟连接的流,其元素是firstStream的所有元素,后跟secondStream的所有元素。
  • 如果两个输入流都是有序的,则对所得到的流进行排序。
  • 如果任一输入流是并行的,则得到的流是平行的。
  • 关闭结果流时,将调用两个输入流的关闭处理程序。

2.Stream concat()合并两个stream

下面用两个数字类型的stream进行合并。
public class Main
{
    public static void main(String[] args)
    {
        Stream<Integer> firstStream = Stream.of(1, 2, 3);
        Stream<Integer> secondStream = Stream.of(4, 5, 6);
         
        Stream<Integer> resultingStream = Stream.concat(firstStream, secondStream);
         
        System.out.println( resultingStream.collect(Collectors.toList()) );
    }
}
程序运行输出:
$title(Console)
[1, 2, 3, 4, 5, 6]

3.合并多个流(Streams)

下面使用4个数字的stream作为演示数据。
import java.util.stream.Collectors;
import java.util.stream.Stream;
import static java.util.stream.Stream.*;
 
public class Main
{
    public static void main(String[] args)
    {
        Stream<Integer> first = Stream.of(1, 2);
        Stream<Integer> second = Stream.of(3,4);
        Stream<Integer> third = Stream.of(5, 6);
        Stream<Integer> fourth = Stream.of(7,8);
         
        Stream<Integer> resultingStream = Stream.concat(first, concat(second, concat(third, fourth)));
         
        System.out.println( resultingStream.collect(Collectors.toList()) );
    }
}
程序输出:
$title(Console)
[1, 2, 3, 4, 5, 6, 7, 8]

4.合并stream并保留唯一性

4.1数字和字符串

在合并两个流  并且保证数据唯一性,
import java.util.stream.Collectors;
import java.util.stream.Stream;
 
public class Main
{
    public static void main(String[] args)
    {
        Stream<Integer> firstStream = Stream.of(1, 2, 3, 4, 5, 6);
        Stream<Integer> secondStream = Stream.of(4, 5, 6, 7, 8, 9);
 
        Stream<Integer> resultingStream = Stream.concat(firstStream, secondStream)
                                                .distinct();
 
        System.out.println( resultingStream.collect(Collectors.toList()) );
    }
}
输出结果:
[1, 2, 3, 4, 5, 6, 7, 8, 9]

4.2自定义对象对比

在合并自定义对象流的情况下,我们可以在流迭代期间删除重复的元素。 我们可以使用对象属性示例为java流创建的distinctByKey()函数
 
import java.util.ArrayList;
import java.util.Map;
import java.util.concurrent.ConcurrentHashMap;
import java.util.function.Function;
import java.util.function.Predicate;
import java.util.stream.Collectors;
import java.util.stream.Stream;
 
public class Main
{
    public static void main(String[] args)
    {
        Stream<Employee> stream1 = getEmployeeListOne().stream();
        Stream<Employee> stream2 = getEmployeeListTwo().stream();
         
        Stream<Employee> resultingStream = Stream.concat(stream1, stream2)
                .filter(distinctByKey(Employee::getFirstName));
         
        System.out.println( resultingStream.collect(Collectors.toList()) );
    }
     
    public static <T> Predicate<T> distinctByKey(Function<? super T, Object> keyExtractor)
    {
        Map<Object, Boolean> map = new ConcurrentHashMap<>();
        return t -> map.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;
    }
 
    private static ArrayList<Employee> getEmployeeListOne()
    {
        ArrayList<Employee> list = new ArrayList<>();
        list.add( new Employee(1l, "Lokesh", "Gupta") );
        list.add( new Employee(5l, "Brian", "Piper") );
        list.add( new Employee(7l, "Charles", "Piper") );
        list.add( new Employee(6l, "David", "Beckham") );
        return list;
    }
     
    private static ArrayList<Employee> getEmployeeListTwo()
    {
        ArrayList<Employee> list = new ArrayList<>();
        list.add( new Employee(2l, "Lokesh", "Gupta") );
        list.add( new Employee(4l, "Brian", "Piper") );
        list.add( new Employee(3l, "David", "Beckham") );
        return list;
    }
}
输出结果

Employee [id=1, firstName=Lokesh, lastName=Gupta],
Employee [id=5, firstName=Brian, lastName=Piper],
Employee [id=7, firstName=Charles, lastName=Piper],
Employee [id=6, firstName=David, lastName=Beckham]]

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编程技术 stream java8